If you want to figure output power by the primary input voltage and current draw (no matter what device is used for amplification) it's much simpler to do all the power measuring in the same kind of units. That means 'avg' power NOT PEP. Then you can make efficiency determinations of the amplifying device (mosfets) that are reasonable.
A 450 watt output with only a 30 amp draw at 12 volts is not going to be possible unless the amplifier is more than commonly efficient (don't hold your breath!).
Primary power is determined by the supply voltage times the current draw, P = E * I, or any of the algebraic variation of that formula. (You can't measure DC using Pep, so don't bother.) So, 30A X 12V = 360 watts input power. Like it or not, the average amplifier is doing really good if it's 50% efficient. So, divide that 360 watts by 2 and you get 180 watts possible for the output. Plus or minus amybe 10% is a reasonable 'fudge factor' so about 150 watts to about 200 watts output is possible (take the low number it's more likely). Follow that all the way through and you can see that 450 watts output is 'advertising', not something you should expect to see. Typical 'seller' or manufacturer B.S., you know? It's really that simple.
- 'Doc