I'll explain this way.
DC circuits when running feeders: The total length of all current carrying conductors must be calculated.
Ex: This power supply hook-up
A: Power supply #1... has #4 ga wire 10 feet long to load (thus 20ft true length) @50 amps
Power supply #2 has #4 ga wire 3 feet (6 feet true length) @50 amps.
Thus, you have a Parrell DC circuit resistance.
You now have an imbalance of voltage drop across each load.
PS#1 equates to 5.1% voltage drop (12v in @load 11.4v)
PS#2 equates to 1.5% voltage drop (12v in @load 11.8v)
This is calculated at roughly room temperature (77 degs F) as the wire heats up due to current surges or usage, the resistance increases, thus the imbalance will increase.
This illustrates possible issues, if one was to use different size conductors on each supply.
EX : PS #1 #4 ga ... PS#2 #8 ga
Those voltage drops across each load becomes even more dramatic.
Having delt with these types of AC or DC circuits with Phasing AC Transformers / DC loads etc. for almost 30 years.
I call tell you it must be considered when building a system.
Even values this small, maintaining the equal balance across each load must be considered. IMHO
Consider this, 2 "phased" power supplies:
What happens to the current draw from each supply when you have a difference in voltage drop across the feeders?
One supply will have a HIGHER current draw than the other when suppling the load.
My worthless 2 cents
All the Best
Gary
That is true Gary. When I said small length differences didn't matter I was thinking the way It would do things. A few inches different won't be an issue yet it is not EXACTLY the same length as was suggested It should be. What I am saying and failed to be clear about above was that you do not need a micrometer to measure the cable lengths. A regular tape measure will do.