laugh your ass off all you want. they sell it because the manufacturer makes it, NOT BECAUSE IT'S DESIGNED FOR ANY PARTICULAR APPLICATION. this is why most hobbyists can't get dual antennas to function properly because they don't have a clue what they're doing and don't understand the principals involved.
what is required to match two 50 ohm loads to a single 50 ohm source is a harness composed of two sections, each consisting of a 1/4 section of line. (1/4 wave transformer) a 1/2 wave line mirrors impedance and a 1/4 wave line inverts impedance. in the case of dual antennas we want to invert the impedances presented by the loads to match them to the source transmitter.
with polyethylene line at .66% VF the length of a 1/4 wave line at cb frequencies is approximately 6' and ANY ODD MULTIPLE.
246 / 27.205 X .66% VF = 5.968' or 5' 11.6"
using foam line @ .78%VF the length is approximately 7' OR ANY ODD MULTIPLE.
246 / 27.205 X .78% VF = 7.053' or 7' 0.6"
so the lengths required for a 1/4 wave transformer based on VF and the frequency in question would be:
6', 18' 30' etc. for polyethylene @ .66% VF
7'. 21' 35' etc. for foam @ .78% VF
since there is no feedline impedance that is close to that value and since we are matching two 50 ohm loads in parallel, (which equals 25 ohms) then two 70 - 75 ohm lines in parallel provides the necessary impedance transformation.
1/4 Matching Section = sqrt ( Z1 * Z2)
sqrt ( 25 * 50 )
sqrt (1250)
35.35 ohms
go google it and if you plan on arguing the point then bring the facts and the math with you.
you're wrong, get over it.